Bulk Update for Performance
A snippet showing how to use bulk_update for faster updates.
# views.py
from .models import Event
def publish_events(request):
events = list(Event.objects.filter(published=False)[:500])
for e in events:
e.published = True
Event.objects.bulk_update(events, ["published"])
return HttpResponse("Updated events.")
Explanation:
- Updates many rows efficiently with a single bulk update call.
- Greatly improves performance when you need to update many rows.
- Category Performance & Optimization
- Total Views 346
- Last Modified 05 May, 2026
- Tags #performance #bulk #update #models
Previous snippet
Bulk Create for Performance
Next snippet